6-[2x-(3x-4)]+1=0

Solution for 6-[2x-(3x-4)]+1=0 equation:

Simplifying
6 + -1[2x + -1(3x + -4)] + 1 = 0

Reorder the terms:
6 + -1[2x + -1(-4 + 3x)] + 1 = 0
6 + -1[2x + (-4 * -1 + 3x * -1)] + 1 = 0
6 + -1[2x + (4 + -3x)] + 1 = 0

Reorder the terms:
6 + -1[4 + 2x + -3x] + 1 = 0

Combine like terms: 2x + -3x = -1x
6 + -1[4 + -1x] + 1 = 0
6 + [4 * -1 + -1x * -1] + 1 = 0
6 + [-4 + 1x] + 1 = 0

Reorder the terms:
6 + -4 + 1 + 1x = 0

Combine like terms: 6 + -4 = 2
2 + 1 + 1x = 0

Combine like terms: 2 + 1 = 3
3 + 1x = 0

Solving
3 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 1x = 0 + -3
1x = 0 + -3

Combine like terms: 0 + -3 = -3
1x = -3

Divide each side by '1'.
x = -3

Simplifying
x = -3